Example #1
__3__
√2+1
STEP ONE
Multiply both the numerator and the denominator by the conjugate. This is the same as the denominator, just with the second term's sign reversed. If there is only one sign in the denominator, don't change the sign.
__3__ (√2-1)
√2+1 (√2-1)
=
3√2-3
_____
2-1
STEP TWO
Solve the rest of the problem. REMEMBER TO REDUCE (if possible)!
3√2-3
_____
2-1
3√2-3
_____
1
= 3√2-3
Do the same for the rest.
Example #2
(√5 + √2)(√5-√2)
multiply the terms together
√2x - √10 +3√2-3
√2x
5-2=3
Example #3
_7_ (√3-1) <-----conjugates
√3+1(√3-1) <-----
7√3 - 7
_____
3 - 1
= 7√3-7
______
2
Example #4
__2__ (√5 + 2)
√5 - √2 (√5+2)
2√5 + 2√2
_______
√25
2√5+2√2
_______
5-2
2√5 + 2√2
________
3
Example #5
__15__ (√14+5)
√14 - 5 (√14+5)
15√14 + 75
__________
√196
15 √14 +75
_________
14 - 25
15√14 + 75
_______
-11
Example #6
4√15 (3√15 - 8)
______
3√15 + 8 (3√15-8)
12√225 - 32 √15
____________
9√225 -
180 - 32√15
________
135 - 64
180 - 32√15
________
71
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